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35n^2-301n+392=0
a = 35; b = -301; c = +392;
Δ = b2-4ac
Δ = -3012-4·35·392
Δ = 35721
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{35721}=189$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-301)-189}{2*35}=\frac{112}{70} =1+3/5 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-301)+189}{2*35}=\frac{490}{70} =7 $
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